On 12/22/05, Daniel Carrera wrote:

Hi all,

How do I write a statement that spans multiple lines?

I have this function:

pythagoras n = [(a,b,c) | a <-[1..n], b <-[1..n], c <-[1..n], a <= b, b < c, a*a + b*b == c*c]

This should all be in one line. I know some ways to make the line shorter, like defining local functions and using 'filter'. But the code would be clearer if I could just make this one statement span several lines.

Indent the second line: pythagoras n = [(a,b,c) | a <-[1..n], b <-[1..n], c <-[1..n], a <= b, b < c, a*a + b*b == c*c] /g -- We have lingered in the chambers of the sea By sea-girls wreathed with seaweed red and brown Till human voices wake us, and we drown.

Daniel Carrera wrote:

Hi all,

How do I write a statement that spans multiple lines?

I have this function:

pythagoras n = [(a,b,c) | a <-[1..n], b <-[1..n], c <-[1..n], a <= b, b < c, a*a + b*b == c*c]

This should all be in one line. I know some ways to make the line shorter, like defining local functions and using 'filter'. But the code would be clearer if I could just make this one statement span several lines.

Haskell's layout rules mean that you have to keep intenting at the beginning of a line to continue a definition. Try something like... pythagoras n = [(a,b,c) | a <- [1..n], b <- [1..n], c <- [1..n], a <= b, b < c, a*a + b*b == c*c ] ...or... pythagoras n = [(a,b,c) | a <- [1..n], b <- [1..n], c <- [1..n], a <= b, b < c, a*a + b*b == c*c ] ...See also... http://www.haskell.org/onlinereport/lexemes.html#lexemes-layout Greg Buchholz