RE: Hashing over equivalence classes

14 Mar
2009
14 Mar
'09
11:52 p.m.
Hi Roman, So are you really talking about an equivalence relation on the function's domain? The reason I ask is that it is well known that "f(a)=f(b)" establishes an equivalence relation on f's co-domain! Vasili
5912
Age (days ago)
5912
Last active (days ago)
0 comments
1 participants
participants (1)
-
Galchin, Vasili