RE: Hashing over equivalence classes
15 Mar
2009
15 Mar
'09
9:22 a.m.
Hi Roman, So are you really talking about an equivalence relation on the function's domain? The reason I ask is that it is well known that "f(a)=f(b)" establishes an equivalence relation on f's co-domain! Vasili
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Galchin, Vasili