RE: Hashing over equivalence classes
            
            
            
                14 Mar
                
                    2009
                
            
            
                14 Mar
                
                '09
                
            
            
            
        
    
                11:52 p.m.
            
        Hi Roman, So are you really talking about an equivalence relation on the function's domain? The reason I ask is that it is well known that "f(a)=f(b)" establishes an equivalence relation on f's co-domain! Vasili
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Galchin, Vasili