Re: [Haskell-cafe] Re: monad subexpressions
 
            
            
            
            
                3 Aug
                
                    2007
                
            
            
                3 Aug
                
                '07
                
            
            
            
        
    
                7:47 a.m.
            
        rewrite *p++=*q++ in haskell?
*p = *(p+1) ; *q = *(q+1)
If that's true then GCC has gone insane, because they are completely different.
Of course you are right, I just observed at the wrong place..., sorry for that.
Though, as any C programmer knows, you really should be using memcpy()
I like to hear that you would reject it either. /BR -- -- Mirko Rahn -- Tel +49-721 608 7504 -- --- http://liinwww.ira.uka.de/~rahn/ ---
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                 Mirko Rahn Mirko Rahn