On 3/19/06, Neil Rutland wrote:

Hi Everyone,

I am completely new to this so my apologies if some of the questions are ill described/directed, but if they are just let me know and i'll try and make the relevent changes.

I chose this one as it seemed the right sort for me with my (rudimentary knowledge), the first question is probably very simple but a bit of a jump for my brain.

Basically i want to add two user entered numbers together to calculate the number of stops between two traint stations so i think i would define that as so:

stops :: int->int->int

I think that says that the function stops takes two integers and returns an integer.

What i'm not entirely sure of is how i'd then write the function itself because i literally want it to have the following form

stops (x,y) = x+y

I think you're looking for: stops x y = x+y Or use your own definition and change the type to stops:: (Int,Int) -> Int It's generally recommended not to send the parameters of your function as a tuple (like you're doing) but rather "one at a time" like the example I gave above. /S -- Sebastian Sylvan +46(0)736-818655 UIN: 44640862

Neil Rutland wrote:

stops :: int->int->int

I think that says that the function stops takes two integers and returns an integer.

This is correct (though as someone else pointed out, Haskell types start with a capital letter).

What i'm not entirely sure of is how i'd then write the function itself because i literally want it to have the following form

stops (x,y) = x+y

As "stops" just adds numbers, it is equivalent to the + operator, so you don't have to write a function at all. It doesn't do any harm to write a function, but the simplest way of expressing "stops" is this: stops :: Int -> Int -> Int stops = (+) One of the benefits of a functional language is that you can assign functions as well as data! Pete