lazy patterns versus where-clauses
21 Jun
2007
21 Jun
'07
4:13 p.m.
Is f(~p(x))=e(x) semantically equivalent to: f(z)=e(x) where p(x)=z?
4:24 p.m.
New subject: [Haskell] Re: lazy patterns versus where-clauses
On Thu, Jun 21, 2007 at 09:18:02AM -0700, Stefan O'Rear wrote:
PS: I saw that twice
Oops, failed to notice the cross-post - I thought it was a double post, sorry. In the future smallish questions should usually be directed to -cafe@ - haskell@ is treated as an announce list. Stefan
7:31 p.m.
Peter Padawitz writes:
Is f(~p(x))=e(x) semantically equivalent to: f(z)=e(x) where p(x)=z?
Yep. See also http://en.wikibooks.org/wiki/Haskell/Laziness#Lazy_pattern_matching regarding lazy patterns. -- -David House, dmhouse@gmail.com
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Stefan O'Rear