On Wed, 21 Dec 2005, Scherrer, Chad wrote:

------------ From: Daniel Carrera

Hey,

The sqrt function is not doing what I want. This is what I want:

round sqrt(2) --------------------------------------------------- Daniel,

A lot of Haskell folks like to avoid parentheses as much as possible, and there's a really convenient way to do this. There is a Prelude function ($) f x = f x which is right-associative, so you can write round $ sqrt x == round (sqrt x) This becomes really convenient when multiple application is involved: print $ round $ sqrt x == print (round (sqrt x))

Doesn't it sometimes feel like the $ operator is Haskell's way of saying "We're not with those Lisp guys, seriously"?