Isaac Jones wrote:

yin writes:

...

./bundle01 <cmd> <arg1> <arg2> ...

I more apoarches, but no one worked. Now I tried this:

m01_mod :: Int -> Int -> Int

What's m01? You define b01 below:

oops! "m01" propably is a halucination of my keyboard :)

...

main = do (cmd:ss) <- getArgs putStrLn ( if (cmd == "mod") then do

You don't need the "do" here. Since the type of the entire "if" statement is a String (not an IO String) this is an error.

it looks more like bash... I'm familiar with it...

...

show (b01_mod (read (ss!!1)) (read (ss!!2))) else do "unknown command!")

Please, send me somethung like this (I need to understand it). I need runing more <cmd>s and with various argument counts and types. All functions "in a bundle" should be in one file.

I need a module Main. So, when I write some function and save it in file funcsXX.hs and compile all the files, the result should be a program, which will execute my functions. I need it to test these functions, because I just started to learn Haskell.

Otherwise, looks roughly correct to me... The program will crash with a meaningless error if they don't enter any args.

Should I handle incorect situations? How does exception in Haskell work... Oh, yeah... solved partialy this problem: delta_encode :: [Int] -> [Int] delta_encode x:y:zs = x : (deltra_encode ((x + y) : zs)) delta_encode _ = _ -- Is this correct, I wroted it from my head delta_decode ... ... main = do (cmd:ss) <- getArgs putStrLn ( if (cmd == "encode") then show (delta_encode (map (read) ss) else if (cmd == "decode") "unknown command!") Thanks! Matej 'Yin' Gagyi