Under the covers of syntax they only have one parameter, but you can write curried lambdas or functions easily: \ a b -> a + b which is equivalent to \ a -> \ b -> a + b and also equivalent to the "normal" function syntax f a b = a + b or f a = \ b -> a + b -Ross On Apr 12, 2009, at 9:09 PM, michael rice wrote:

My question was meant in the context of the makeVerifier function, which is passed a lambda expression. It's my understanding that Haskell lambda expressions can have only a single parameter, which is why I changed the function parameter to a pair, (i,d).

How would it be done otherwise?

Michael

--- On Sun, 4/12/09, Daniel Fischer wrote:

From: Daniel Fischer Subject: Re: [Haskell-cafe] Functions that return functions To: "michael rice" Cc: haskell-cafe@haskell.org Date: Sunday, April 12, 2009, 7:20 PM

Am Montag 13 April 2009 01:09:22 schrieb michael rice:

...

Example please.

Michael

Curried:

f :: a -> b -> c

amenable to partial application.

Uncurried:

g :: (a,b) -> c

not easy to apply partially.

The Prelude contains

curry :: ((a,b) -> c) -> (a -> b -> c)

uncurry :: (a -> b -> c) -> ((a,b) -> c)

to convert if needed.

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