Re: [Haskell-cafe] Missing a "Deriving"?

Belay that last question. I just realized that its the const function being used rather than a constant declaration in const Nothing and const [].
MIchael
--- On Sat, 5/30/09, David Menendez
That works. but it gives just a single solution [1,2,3] when there are supposed to be two [[1,2,3],[1,4,3]]. Of course the code in YAHT may be in error.
Works for me. *Main> searchAll g 1 3 :: [[Int]] [[1,2,3],[1,4,3]] *Main> searchAll g 1 3 :: Maybe [Int] Just [1,2,3] *Main> searchAll g 1 3 :: Failable [Int] Success [1,2,3]
Also, how the heck does Haskell decide which "success", "failure", "augment", and "combine" to use in function "searchAll", since there are five possibilities.
*Main> :t searchAll
searchAll :: (Computation c) => Graph t t1 -> Int -> Int -> c [Int]
The way searchAll is written, the choice of which functions to use
depends on the type variable c. That's determined by the calling
context of searchAll, which is why you need to provide a type
signature when using it at the GHCi command line.
--
Dave Menendez
participants (1)
-
michael rice