Belay that last question. I just realized that its the const function being used rather than a constant declaration in const Nothing and const []. MIchael --- On Sat, 5/30/09, David Menendez <dave@zednenem.com> wrote: From: David Menendez <dave@zednenem.com> Subject: Re: [Haskell-cafe] Missing a "Deriving"? To: "michael rice" <nowgate@yahoo.com> Cc: "Miguel Mitrofanov" <miguelimo38@yandex.ru>, haskell-cafe@haskell.org Date: Saturday, May 30, 2009, 9:33 PM On Sat, May 30, 2009 at 9:00 PM, michael rice <nowgate@yahoo.com> wrote:

That works. but it gives just a single solution [1,2,3] when there are supposed to be two [[1,2,3],[1,4,3]]. Of course the code in YAHT may be in error.

Works for me. *Main> searchAll g 1 3 :: [[Int]] [[1,2,3],[1,4,3]] *Main> searchAll g 1 3 :: Maybe [Int] Just [1,2,3] *Main> searchAll g 1 3 :: Failable [Int] Success [1,2,3]

Also, how the heck does Haskell decide which "success", "failure", "augment", and "combine" to use in function "searchAll", since there are five possibilities.

*Main> :t searchAll searchAll :: (Computation c) => Graph t t1 -> Int -> Int -> c [Int] The way searchAll is written, the choice of which functions to use depends on the type variable c. That's determined by the calling context of searchAll, which is why you need to provide a type signature when using it at the GHCi command line. -- Dave Menendez <dave@zednenem.com> <http://www.eyrie.org/~zednenem/>