what's the definition of "satisfy" and "<?>" ?
I cannot understand the following code very well as i donot know the definition of "satisfy" and "<?>". -- | Case-insensitive variant of Parsec's 'char' function. caseChar :: Char -> GenParser Char a Char caseChar c = satisfy (\x -> toUpper x == toUpper c) -- | Case-insensitive variant of Parsec's 'string' function. caseString :: String -> GenParser Char a () caseString cs = mapM_ caseChar cs <?> cs Would somebody mind to explain the code in detail ? Sincerely!
On Thu, May 21, 2009 at 2:10 PM, z_axis@163.com
I cannot understand the following code very well as i donot know the definition of "satisfy" and "".
Did you check out the document of parsec? You can find definitions for 'satisty' and '' in Text.ParserCombinators.Parsec.Char and Text.ParserCombinators.Prim, respectively. lee
"z_axis@163.com"
I cannot understand the following code very well as i donot know the definition of "satisfy" and "".
Yes. Just look at the Parsec documentation, preferably Parsec 3, because Parsec versions prior to 3 were not well documented.
-- | Case-insensitive variant of Parsec's 'char' function. caseChar :: Char -> GenParser Char a Char caseChar c = satisfy (\x -> toUpper x == toUpper c)
-- | Case-insensitive variant of Parsec's 'string' function. caseString :: String -> GenParser Char a () caseString cs = mapM_ caseChar cs cs
This code looks incorrect to me. It should read: caseString :: String -> GenParser Char a () caseString cs = Parsec.try (mapM_ caseChar cs) cs Greets, Ertugrul. -- nightmare = unsafePerformIO (getWrongWife >>= sex) http://blog.ertes.de/
participants (3)
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Ertugrul Soeylemez -
Lee Duhem -
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