I did that, the slash is a typo. I was looking at the Lua reference manual and it says that lua_loadfile uses lua_load[1] which outputs 0 if successful. Appreciate the quick response. -deech [1] http://www.lua.org/manual/5.1/manual.html#lua_load On Sat, Oct 23, 2010 at 2:49 AM, Gracjan Polak wrote:

Change this:

succ <- Lua.loadfile l "/Haskell2Lua.lua"

into

succ <- Lua.loadfile l "Haskell2Lua.lua"

Note that 0 at the beginning says there was an error loading a script.

I should make it an exception I guess...

-- Gracjan

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That worked. Thank you! -deech On Sat, Oct 23, 2010 at 1:49 PM, Claude Heiland-Allen < claudiusmaximus@goto10.org> wrote:

Hi Aditya,

The problem is not that the file was not loaded, but that in Lua, loading a file only loads it and does not execute it; Lua is a "dynamic" language, by which I mean that definitions are created through execution.

Attached is a simple example, note that there is no proper error checking - you probably want to check the results rather than pattern matching against constants.

Thanks,

Claude

On 23/10/10 03:21, aditya siram wrote:

...

Hi all, I'm having some issues calling Lua functions from Haskell. I have the following in "Haskell2Lua.lua": function hello () return "hello world" end

And my Haskell file "Haskell2Lua.hs" looks like this: import qualified Scripting.Lua as Lua

main = do

l<- Lua.newstate

Lua.openlibs l

succ<- Lua.loadfile l "/Haskell2Lua.lua"

print succ

Lua.callproc l "hello" ""

Lua.close l

When I compile and run this file I get: 0 Haskell2Lua: user error (attempt to call a nil value)

I have tried some variations on calling the function including: Lua.callproc l "hello" Lua.callfunc l "hello" Lua.callfunc l "hello" ""

I know the Lua bridge is working because the following works:

Lua.callproc l "print" "Hello from Lua"

Any help is appreciated! -deech

-- http://claudiusmaximus.goto10.org

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