I still can't remember how guards are treated in Haskell. Here is the code snippet in question: foo a | a == 1 = 6 foo a | a == 2 = 7 foo a = 8 Would Haskell fall through to the third alternative if a is not equal to 1 or 2. I know that this can be rewritten more sanely, but I just consider guard behavior. What would be the value of (foo 3)? -- vir http://vir.comtv.ru/
On Thu, Sep 20, 2007 at 05:20:46PM +0400, Victor Nazarov wrote:
I still can't remember how guards are treated in Haskell. Here is the code snippet in question:
foo a | a == 1 = 6 foo a | a == 2 = 7 foo a = 8
Would Haskell fall through to the third alternative if a is not equal to 1 or 2. I know that this can be rewritten more sanely, but I just consider guard behavior. What would be the value of (foo 3)?
8. It falls through if no guards in a rhs match. Stefan
participants (2)
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Stefan O'Rear -
Victor Nazarov