How about zipMap = zipWith ($) - Conal -----Original Message----- From: Eric Allen Wohlstadter [mailto:wohlstad@cs.ucdavis.edu] Sent: Thursday, March 08, 2001 6:19 PM To: haskell-cafe@haskell.org Subject: zips and maps I find myself very often needing to use this function and was wondering if there was already a way to do this using zip,maps, and folds. zipMap::[a->b]->[a]->[b] zipMap [] _ = [] zipMap _ [] = [] zipMap (f:fs) (x:xs) = (f x):(zipMap fs xs) Alternatively I can get the same affect like this: fstOnSnd::(a->b,a)->b fstOnSnd (f,x) = f x zipMap::[a->b]->[a]->[b] zipMap fs xs = map fstOnSnd (zip fs xs) Both require me to invent some new function (or use a lambda) which I am trying to avoid. If it is unavoidable then can someone think of a better name then zipMap? Eric Wohlstadter UCDavis Software Engineering _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe