First, I'd refer you to this list's rules on homework, and what people will or won't answer. Secondly to that though, rather than provide a solution, I'll give you an idea that may lead to you coming up with a solution. First, try and write a function that can test if your first list is at the start of the second list:

startlist [2,3] [2,3,4,5] True startlist [2,3] [1,2,3,4] False

Then use this function to write your sublist function. Hope that helps Tom Davie On 24 Apr 2008, at 10:29, cetin tozkoparan wrote:

I have a problem which i can't solve. Is there any one who has an idea? Two lists is sent as parameter to a function. If second list contains first list, return true, else return false. This comparision must be in order of first list. You can look at examples.

function type as follows:

sublist:: [a] -> [a] -> Bool

examples:

For instance [2,4,5] list is sub list of [3,7,2,4,5,9] list but not of [3,7,4,2,5,9] list.

sublist [2,8] [1,5,6,2,4,7,8,2] False

sublist [1,2,3] [0,1,2,3,4,5,6] True sublist [5,4] [1,4,5,7,8,3,5,4] True sublist [1,2,4,3,4,5,7,8,9,5] [8,2,3,1,2,4,3,4,5,7,8,9,5,1,6,2] True

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