Jason, Thank you for your answer. I haven't found unliterate capability in GHC, but I found unlit function in Distribution.Simple.PreProcess.Unlit, which do the things I needed. Best regards, Vasyl 2009/4/14 Jason Dagit :

On Mon, Apr 13, 2009 at 3:37 PM, Vasyl Pasternak wrote:

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Hello,

Are there ability to parse literate haskell source with Language.Haskell.Parser, or maybe there is some tool, which converts .lhs files to .hs ?

You can ask GHC to remove the literate bits. I think the command is called 'unlit' but check the GHC manual to be sure.

Jason

Niklas, I suspected that haskell-src-exts should have this function, but it was undocumented :) Thank you for the tip. Best regards, Vasyl 2009/4/14 Niklas Broberg :

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Are there ability to parse literate haskell source with Language.Haskell.Parser, or maybe there is some tool, which converts .lhs files to .hs ?

Use the haskell-src-exts package instead of haskell-src. The function parseFile in Language.Haskell.Exts will de-literate the file for you if the suffix is .lhs.

Cheers,

/Niklas