what is the purpose of GHC.Exts.lazy?

1 Dec
2012
1 Dec
'12
5:42 p.m.
docs say: The call '(lazy e)' means the same as e, but lazyhttp://hackage.haskell.org/packages/archive/base/latest/doc/html/GHC-Exts.ht... has a magical strictness property: it is lazy in its first argument, even though its semantics is strict. why do i want to use magic during strictness analysis?
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jared simpson