Just to clarify, here is the sample haskell code that I am using - {-# LANGUAGE ForeignFunctionInterface #-} module Glue where import Foreign.C.String import qualified Control.Concurrent as CC funHaskell :: CString -> IO Int funHaskell cstr = do putStrLn "Haskell function called" str <- peekCString cstr CC.forkIO $ doForever str CC.threadDelay 2000000 return 0 doForever str = do putStrLn "Hello World forever" CC.threadDelay 1000000 doForever str foreign export stdcall funHaskell :: CString -> IO Int When I call "funHaskell" from my C program, "Hello World forever" gets printed about twice - I think its because funHaskell waits for about 2 seconds before returning. However, once back in C land, the doForever function stops to execute. I was wondering if there is some setting that would allow the threads sparked to continue execute. Regards, Kashyap On Thu, Feb 28, 2013 at 4:39 PM, C K Kashyap wrote:

Hi All,

Say I have a haskell function 'f' that does a forkIO and starts an action "a". I create a DLL of this haskell code and inovke "f" from C. Can I expect the "a" to continue to run once "f" has returned to C?

Regards, Kashyap