Hello! I'm not sure if this is what you're asking for, as it doesn't fit that line of code. 'LitT' is a data constructor not a type constructor. So instead it'd be reifyType (LitT ...) = ConE 'LitT ... If this is what you're looking for, then 'lift' is what you want: http://hackage.haskell.org/packages/archive/th-lift/latest/doc/html/Language-Haskell-TH-Lift.html<http://hackage.haskell.org/packages/archive/th-lift/0.5.5/doc/html/Language-Haskell-TH-Lift.html> In particular, I recommend using this package of template haskell orphans, rather than deriving your own: http://hackage.haskell.org/package/th-orphans Hope that helps! -Michael On Fri, Jul 12, 2013 at 4:45 AM, Jose A. Lopes <jabolopes@google.com> wrote:

Hello everyone,

Is there a way to automatically reify a type ? In other words, to do the following:

reifyType (LitT ...) = ConT ''LitT ...

I am using Template Haskell and I want the generated code to have access to Type datatypes that were available to the Template Haskell code.

Cheers, Jose

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