Is it possible to write a Haskell script that uses a module that is also going to be interpreted? Like, say: #!/usr/bin/runhaskell module Main (main) where import OtherModule main = (...) ---- where OtherModule is available in, say, OtherModule.hs and not in the already compiled and installed library? Thanks, Maurício
As long as OtherModule is in the same directory, Main should have no trouble finding it. Do you mean like this? $ ls Greet.hs hello* $ cat hello #!/usr/bin/env runghc module Main where import Greet main = putStrLn (greet "world") $ cat Greet.hs module Greet (greet) where greet :: String -> String greet s = "hello " ++ s $ ./hello hello world Greg On 2009-Jun-26, Maurício wrote:
Is it possible to write a Haskell script that uses a module that is also going to be interpreted? Like, say:
#!/usr/bin/runhaskell
module Main (main) where import OtherModule main = (...)
----
where OtherModule is available in, say, OtherModule.hs and not in the already compiled and installed library?
Thanks, Maurício
_______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
-- ___ ___ __ _ / _ \ / _ \| | | | Gregory D. Weber, Associate Professor / /_\// / | | | /\ | | Indiana University East / /_\\/ /__| | |/ \| | http://mypage.iu.edu/~gdweber/ \____/\_____/\___/\__/ Tel. (765) 973-8420; FAX (765) 973-8550
participants (2)
-
Gregory D. Weber -
Maurício