The function

app1 f x = f >>= ($ x) or equivalently app2 f x = join (f <*> pure x)

with type Monad m => m (a -> m b) -> a -> m b ? Hoogle did not help. Jacques PS: a nice point-free version would be appreciated as well. I can easily change app1 and app2 myself to point-free with enough applications of flip, . and $, but none of those are 'nice'.