Adam, I used TH because I wanted a non-programmer to write simple statements from data sheets that generated code for a programmer. My ignorance may prove my undoing, but if I learn something by going down a rabbit hole, I can recover. I don’t need to implement g necessarily, as it is part of a larger function generating other TH code, f would be fine. The goal is to have a non-programmer write something like: $(makeCommandData (mkName "RegTCA9535") ["INPUT_PORT_0", "INPUT_PORT_1", "OUTPUT_PORT_0", "OUTPUT_PORT_1", "POLARITY_INVERSION_PORT_0", "POLARITY_INVERSION_PORT_1", "CONFIGURATION_PORT_0", "CONFIGURATION_PORT_1"]) (makeBitData (mkName "TCA9535_INPUT_PORT_0_BITS") [mkName "I0_7", "I0_6", "I0_5", "I0_4", "I0_3", "I0_2", "I0_1", "I0_0”]) MORE REGISTERS HERE and generate a complete API that works off a list of bits, and read/writes SMBus. I have a GSOC project posted here: http://elinux.org/Minnowboard:GSoC2015 The code I am working on here is kind of starter code for that. I already have an SMBus API and impl as well on a MinnowBoardMax running Ubuntu. If any students are interested, follow the link. Mike On Mar 3, 2015, at 6:03 AM, adam vogt wrote:

Hi Mike,

Is there some reason you decided to use TH, when it looks like you can write:

f :: a -> Binary (Maybe a) f con = do v <- BG.getBit return (do guard v; Just con)

makeBits :: [a] -> Binary [a] makeBits con = catMaybes <$> mapM f con

and have the TH part be much smaller:

toCons :: [Name] -> ExpQ toCons = listE . map conE

makeBits $(toCons bitNames)

If you really do need to generate code, let me suggest

combine :: [ExpQ] -> ExpQ combine = foldr1 (\ a b -> [| $a >>= $b |])

together with

g :: Name -> ExpQ g name = [| \bits -> ifM getBit ((return $(conE name) : bits) (return bits) |]

gets you

makeBits = combine . map g

Or you could keep the recursion explicit and write the first clause of your makeBits:

makeBits [name] = g name -- g as above

Regards, Adam

On Tue, Mar 3, 2015 at 1:05 AM, Michael Jones wrote:

...

I’m at wits end as to how to express a monadic expression in TH. I’ll give here two ways to express a non TH version, and then a TH expression that does not quite work. It generates code that compiles, but it does not evaluate properly like the non TH version. Fundamentally, the problem is use of a recursive function using quasi quoting similar to what is in the standard Show example.

Perhaps someone will have an idea on how to fix it. I have made several attempts and failed.

Non TH Example A: Do notation —————————————

let r = BG.runBitGet flags (do let bits = [] v <- BG.getBit bits <- return $ if v then I1_7:bits else bits v <- BG.getBit bits <- return $ if v then I1_6:bits else bits v <- BG.getBit bits <- return $ if v then I1_5:bits else bits v <- BG.getBit bits <- return $ if v then I1_4:bits else bits v <- BG.getBit bits <- return $ if v then I1_3:bits else bits v <- BG.getBit bits <- return $ if v then I1_2:bits else bits v <- BG.getBit bits <- return $ if v then I1_1:bits else bits v <- BG.getBit bits <- return $ if v then I1_0:bits else bits

return $! bits)

Non TH Example B: Bind notation ——————————————

let r = BG.runBitGet flags ( return [] >>= (\bits -> ifM BG.getBit (return $ I0_7:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_6:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_5:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_4:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_3:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_2:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_1:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_0:bits) (return $ bits)))

A TH for Example B: ————————

let bitsP = varP $ mkName "bits" let bitsE = varE $ mkName "bits" let makeBits [] = [| "" |] makeBits (name:names) = [| (\bits -> ifM BG.getBit (return $ $(conE name) : $bitsE) (return $ $bitsE)) >>= $(makeBits names) |] parse <- [d| $(varP (mkName $ "parse" ++ nameBase name)) = do flags <- G.getByteString 1 let r = BG.runBitGet flags (return [] >>= $(makeBits bitNames)) case r of Left error -> fail error Right x -> return x |]

This generates:

parseTCA9535_INPUT_PORT_0_BITS = do {flags_0 <- Data.Binary.Strict.Get.getByteString 1; let r_1 = Data.Binary.Strict.BitGet.runBitGet flags_0 (GHC.Base.return [] GHC.Base.>>= ((\bits_2 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_7 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_3 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_6 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_4 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_5 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_5 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_4 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_6 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_3 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_7 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_2 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_8 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_1 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_9 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_0 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= "")))))))));

Problems with TH ————————

The problem is the () that interferes with the order of evaluation, and the termination at the end ( “” ). I’m no so worried about the termination. I can put something harmless there. The parens are the main problem. Calling a quasi quoter recursively is the cause, as it nests the evaluation.

I tried things like building the bits in a list, but that does not work because the BG.getBit has to run in the BitGit monad. I know I can write a simple evaluation that just returns a list of Bools and only TH for bit names, but in the final version the size of bit fields needs to be dynamic, so I need to dynamically generate code piece by piece.

I would prefer to use quasi quoting rather than build the whole thing with data types so that it is more readable.

If anyone knows of a module on hackage that does something similar, perhaps you can point me to that so I can study it.

Thanks…Mike

_______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/haskell-cafe

Adam, I recoded it like this: let bitsP = varP $ mkName "bits" let bitsE = varE $ mkName "bits" let combine :: [ExpQ] -> ExpQ combine = foldr1 (\ a b -> [| $a >>= $b |]) let g :: Name -> ExpQ g name = [| \bits -> ifM BG.getBit (return $ $(conE name) : $bitsE) (return $bitsE) |] let makeBits = combine . map g parse <- [d| $(varP (mkName $ "parse" ++ nameBase name)) = do flags <- G.getByteString 1 let r = BG.runBitGet flags (do let $bitsP = [] (return [] >>= $(makeBits bitNames)) return $! $bitsE) case r of Left error -> fail error Right x -> return x |] Which generates this: let bits = []; GHC.Base.return [] GHC.Base.>>= ((\bits_2 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_7 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_3 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_6 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_4 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_5 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_5 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_4 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_6 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_3 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_7 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_2 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_8 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_1 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= (\bits_9 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_0 GHC.Types.: bits)) (GHC.Base.return bits))))))))); But it does not compile due to the nesting brackets. The fold nests the functions just like my recursive quasi quoting. So I think the real question is how to connect each function end to end, which is more like composition using the >>= operation. From some previous things I tried, I think the code in the quasi quote must be a complete expression, which makes sense to me. But that is what makes it hard to glue together. Any ideas? Mike On Mar 3, 2015, at 6:03 AM, adam vogt wrote:

Hi Mike,

Is there some reason you decided to use TH, when it looks like you can write:

f :: a -> Binary (Maybe a) f con = do v <- BG.getBit return (do guard v; Just con)

makeBits :: [a] -> Binary [a] makeBits con = catMaybes <$> mapM f con

and have the TH part be much smaller:

toCons :: [Name] -> ExpQ toCons = listE . map conE

makeBits $(toCons bitNames)

If you really do need to generate code, let me suggest

combine :: [ExpQ] -> ExpQ combine = foldr1 (\ a b -> [| $a >>= $b |])

together with

g :: Name -> ExpQ g name = [| \bits -> ifM getBit ((return $(conE name) : bits) (return bits) |]

gets you

makeBits = combine . map g

Or you could keep the recursion explicit and write the first clause of your makeBits:

makeBits [name] = g name -- g as above

Regards, Adam

On Tue, Mar 3, 2015 at 1:05 AM, Michael Jones wrote:

...

I’m at wits end as to how to express a monadic expression in TH. I’ll give here two ways to express a non TH version, and then a TH expression that does not quite work. It generates code that compiles, but it does not evaluate properly like the non TH version. Fundamentally, the problem is use of a recursive function using quasi quoting similar to what is in the standard Show example.

Perhaps someone will have an idea on how to fix it. I have made several attempts and failed.

Non TH Example A: Do notation —————————————

let r = BG.runBitGet flags (do let bits = [] v <- BG.getBit bits <- return $ if v then I1_7:bits else bits v <- BG.getBit bits <- return $ if v then I1_6:bits else bits v <- BG.getBit bits <- return $ if v then I1_5:bits else bits v <- BG.getBit bits <- return $ if v then I1_4:bits else bits v <- BG.getBit bits <- return $ if v then I1_3:bits else bits v <- BG.getBit bits <- return $ if v then I1_2:bits else bits v <- BG.getBit bits <- return $ if v then I1_1:bits else bits v <- BG.getBit bits <- return $ if v then I1_0:bits else bits

return $! bits)

Non TH Example B: Bind notation ——————————————

let r = BG.runBitGet flags ( return [] >>= (\bits -> ifM BG.getBit (return $ I0_7:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_6:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_5:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_4:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_3:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_2:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_1:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_0:bits) (return $ bits)))

A TH for Example B: ————————

let bitsP = varP $ mkName "bits" let bitsE = varE $ mkName "bits" let makeBits [] = [| "" |] makeBits (name:names) = [| (\bits -> ifM BG.getBit (return $ $(conE name) : $bitsE) (return $ $bitsE)) >>= $(makeBits names) |] parse <- [d| $(varP (mkName $ "parse" ++ nameBase name)) = do flags <- G.getByteString 1 let r = BG.runBitGet flags (return [] >>= $(makeBits bitNames)) case r of Left error -> fail error Right x -> return x |]

This generates:

parseTCA9535_INPUT_PORT_0_BITS = do {flags_0 <- Data.Binary.Strict.Get.getByteString 1; let r_1 = Data.Binary.Strict.BitGet.runBitGet flags_0 (GHC.Base.return [] GHC.Base.>>= ((\bits_2 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_7 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_3 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_6 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_4 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_5 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_5 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_4 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_6 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_3 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_7 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_2 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_8 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_1 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_9 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_0 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= "")))))))));

Problems with TH ————————

The problem is the () that interferes with the order of evaluation, and the termination at the end ( “” ). I’m no so worried about the termination. I can put something harmless there. The parens are the main problem. Calling a quasi quoter recursively is the cause, as it nests the evaluation.

I tried things like building the bits in a list, but that does not work because the BG.getBit has to run in the BitGit monad. I know I can write a simple evaluation that just returns a list of Bools and only TH for bit names, but in the final version the size of bit fields needs to be dynamic, so I need to dynamically generate code piece by piece.

I would prefer to use quasi quoting rather than build the whole thing with data types so that it is more readable.

If anyone knows of a module on hackage that does something similar, perhaps you can point me to that so I can study it.

Thanks…Mike

_______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/haskell-cafe

Adam, Attached is a working function. I have not followed up on your final suggestions, because I am still considering the best way to represent bit fields, empty bits, mixed read/write only bits, etc. I’ll optimize when I find a final structure. But at least I was able to get a prototype working that could twiddle bits on an I2C device and I know how to build expressions with >>=. Many many thanks. Mike. let bitsP = varP $ mkName "bits" let bitsE = varE $ mkName "bits" let combine :: [ExpQ] -> ExpQ combine = foldl1 (\ a b -> [| $a >>= $b |]) let g :: Name -> ExpQ g regName' = [| \bits -> ifM BG.getBit (return $ (((fromIntegral . fromEnum) $(conE regName'))::Word16) : $bitsE) (return $bitsE) |] let h = [| return [] |] let makeBits names = combine (h : map g names) parse <- [d| $(varP (mkName $ "parse" ++ nameBase regName')) = do flags <- G.getByteString 1 let r = BG.runBitGet flags (do let $bitsP = [] $(makeBits (reverse bitNames')) return $! $bitsE) case r of Left error -> fail error Right x -> return x |] On Mar 4, 2015, at 8:44 PM, adam vogt wrote:

Hi Mike

Use foldl1 then.

But I think you're better off not unrolling the loop(s) that the "makeBits $(toCons bitNames)" option does, since that makes your code shorter so there are less things that go wrong. For example,

A. thinking >>= is infixr in your "Non TH Example B" (the current issue)

B. suspicious things like using $bitsE instead of bits. Depending on what bitsE is defined as, it doesn't have to evaluate to the closest bits-named variable: https://gist.github.com/aavogt/c894be768539ac9feb06.

Regards,

Adam

Adam,

I recoded it like this:

let bitsP = varP $ mkName "bits" let bitsE = varE $ mkName "bits" let combine :: [ExpQ] -> ExpQ combine = foldr1 (\ a b -> [| $a >>= $b |]) let g :: Name -> ExpQ g name = [| \bits -> ifM BG.getBit (return $ $(conE name) : $bitsE) (return $bitsE) |]

let makeBits = combine . map g parse <- [d| $(varP (mkName $ "parse" ++ nameBase name)) = do flags <- G.getByteString 1 let r = BG.runBitGet flags (do let $bitsP = [] (return [] >>= $(makeBits bitNames)) return $! $bitsE) case r of Left error -> fail error Right x -> return x |]

Which generates this:

let bits = []; GHC.Base.return [] GHC.Base.>>= ((\bits_2 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_7 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_3 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_6 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_4 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_5 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_5 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_4 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_6 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_3 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_7 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_2 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= ((\bits_8 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_1 GHC.Types.: bits)) (GHC.Base.return bits)) GHC.Base.>>= (\bits_9 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_0 GHC.Types.: bits)) (GHC.Base.return bits)))))))));

But it does not compile due to the nesting brackets. The fold nests the functions just like my recursive quasi quoting. So I think the real question is how to connect each function end to end, which is more like composition using the >>= operation.

From some previous things I tried, I think the code in the quasi quote must be a complete expression, which makes sense to me. But that is what makes it hard to glue together.

Any ideas?

Mike

On Mar 3, 2015, at 6:03 AM, adam vogt wrote:

...

Hi Mike,

Is there some reason you decided to use TH, when it looks like you can write:

f :: a -> Binary (Maybe a) f con = do v <- BG.getBit return (do guard v; Just con)

makeBits :: [a] -> Binary [a] makeBits con = catMaybes <$> mapM f con

and have the TH part be much smaller:

toCons :: [Name] -> ExpQ toCons = listE . map conE

makeBits $(toCons bitNames)

If you really do need to generate code, let me suggest

combine :: [ExpQ] -> ExpQ combine = foldr1 (\ a b -> [| $a >>= $b |])

together with

g :: Name -> ExpQ g name = [| \bits -> ifM getBit ((return $(conE name) : bits) (return bits) |]

gets you

makeBits = combine . map g

Or you could keep the recursion explicit and write the first clause of your makeBits:

makeBits [name] = g name -- g as above

Regards, Adam

On Tue, Mar 3, 2015 at 1:05 AM, Michael Jones wrote:

...

I’m at wits end as to how to express a monadic expression in TH. I’ll give here two ways to express a non TH version, and then a TH expression that does not quite work. It generates code that compiles, but it does not evaluate properly like the non TH version. Fundamentally, the problem is use of a recursive function using quasi quoting similar to what is in the standard Show example.

Perhaps someone will have an idea on how to fix it. I have made several attempts and failed.

Non TH Example A: Do notation —————————————

let r = BG.runBitGet flags (do let bits = [] v <- BG.getBit bits <- return $ if v then I1_7:bits else bits v <- BG.getBit bits <- return $ if v then I1_6:bits else bits v <- BG.getBit bits <- return $ if v then I1_5:bits else bits v <- BG.getBit bits <- return $ if v then I1_4:bits else bits v <- BG.getBit bits <- return $ if v then I1_3:bits else bits v <- BG.getBit bits <- return $ if v then I1_2:bits else bits v <- BG.getBit bits <- return $ if v then I1_1:bits else bits v <- BG.getBit bits <- return $ if v then I1_0:bits else bits

return $! bits)

Non TH Example B: Bind notation ——————————————

let r = BG.runBitGet flags ( return [] >>= (\bits -> ifM BG.getBit (return $ I0_7:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_6:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_5:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_4:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_3:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_2:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_1:bits) (return $ bits)) >>= (\bits -> ifM BG.getBit (return $ I0_0:bits) (return $ bits)))

A TH for Example B: ————————

let bitsP = varP $ mkName "bits" let bitsE = varE $ mkName "bits" let makeBits [] = [| "" |] makeBits (name:names) = [| (\bits -> ifM BG.getBit (return $ $(conE name) : $bitsE) (return $ $bitsE)) >>= $(makeBits names) |] parse <- [d| $(varP (mkName $ "parse" ++ nameBase name)) = do flags <- G.getByteString 1 let r = BG.runBitGet flags (return [] >>= $(makeBits bitNames)) case r of Left error -> fail error Right x -> return x |]

This generates:

parseTCA9535_INPUT_PORT_0_BITS = do {flags_0 <- Data.Binary.Strict.Get.getByteString 1; let r_1 = Data.Binary.Strict.BitGet.runBitGet flags_0 (GHC.Base.return [] GHC.Base.>>= ((\bits_2 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_7 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_3 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_6 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_4 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_5 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_5 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_4 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_6 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_3 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_7 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_2 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_8 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_1 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= ((\bits_9 -> Control.Conditional.ifM Data.Binary.Strict.BitGet.getBit (GHC.Base.return GHC.Base.$ (I0_0 GHC.Types.: bits)) (GHC.Base.return GHC.Base.$ bits)) GHC.Base.>>= "")))))))));

Problems with TH ————————

The problem is the () that interferes with the order of evaluation, and the termination at the end ( “” ). I’m no so worried about the termination. I can put something harmless there. The parens are the main problem. Calling a quasi quoter recursively is the cause, as it nests the evaluation.

I tried things like building the bits in a list, but that does not work because the BG.getBit has to run in the BitGit monad. I know I can write a simple evaluation that just returns a list of Bools and only TH for bit names, but in the final version the size of bit fields needs to be dynamic, so I need to dynamically generate code piece by piece.

I would prefer to use quasi quoting rather than build the whole thing with data types so that it is more readable.

If anyone knows of a module on hackage that does something similar, perhaps you can point me to that so I can study it.

Thanks…Mike

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