Hello,
I also think that the first version is the correct one (i.e., the
result is _|_).
-Iavor
On 3/16/07, Ross Paterson
On Fri, Mar 16, 2007 at 05:40:17PM +0100, apfelmus@quantentunnel.de wrote:
The translation
q = FinCons 3 q === (by Haskell 98 report 4.2.1/Strictness Flags/Translation q = (FinCons $ 3) $! q
is rather subtle: the first FinCons is a strict constructor whereas the second is "the real constructor". In other words, the translation loops as we could (should?) apply
FinCons => \x y -> FinCons x $! y => \x y -> (\x' y' -> FinCons x' $! y') x $! y => ...
ad infinitum.
Yes, perhaps that ought to be fixed. But even so, this clearly implies that
FinCons 3 _|_ = _|_
and thus that q is _|_ and nhc98/yhc have a bug.
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