Re: [Haskell] Question about Infix/Postfix Operators in Haskell
18 Oct
2004
18 Oct
'04
8:13 a.m.
One easy way:
plus :: Int -> Int -> Int plus x y = x + y
times2 x = x `plus` x
-- Janis Voigtlaender http://wwwtcs.inf.tu-dresden.de/~voigt/ mailto:voigt@tcs.inf.tu-dresden.de
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Janis Voigtlaender