Re: Implict parameters and monomorphism
3 May
2001
3 May
'01
7:48 a.m.
But a term with an "implicit" argument is a function no matter how you turn it, you just don't write the argument explicitely. I don't buy that. You could equally well say a term with a free variable is a "function" (of the environment): sure it is, but if it's bound with a let then the function is called only once. John
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John Hughes