13 Mar
2001
13 Mar
'01
12:29 a.m.
I think so. The language grammar requires (if I read it correctly) that the expr in an aexp of the form (op expr) have a higher priority than op. On Mon, 12 Mar 2001 andreas.marth@daimlerchrysler.com wrote:
So why is (^2*3) not equvalent to \a->a^2*3 ?
Because it's being parsed as (^(2*3)) when it should be rejected. Jón -- Jón Fairbairn Jon.Fairbairn@cl.cam.ac.uk 31 Chalmers Road jf@cl.cam.ac.uk Cambridge CB1 3SZ +44 1223 570179 (pm only, please)