Re: Adding swap/compose functions to Data.Tuple and Data.Function

On Tue, Nov 20, 2012 at 11:14 AM, John Wiegley wrote:

compose :: [(a -> a)] -> a -> a compose = foldr (.) id

composeM :: [(a -> m a)] -> a -> m a composeM = foldr (<=<) return

I don't think these offer any value beyond saving a couple of keystrokes. -1 from me.