Re: Generalize IsString

This would require desugaring string literals using `fromListN`, which would require GHC effort. Also, consider ByteString. Is `Item ByteString` `Word8` or `Char`? Additionally, I'm not convinced this coupling really buys us much. You could always define `fromString = fromList`. On Fri, Jun 5, 2020, 11:12 PM Dannyu NDos wrote:

As we already have IsList, shouldn't we just do this?

class (IsList l, Item l ~ Char) => IsString l

instance (a ~ Char) => IsString [a] instance (a ~ Char) => IsString (NonEmpty a) instance (a ~ Char) => IsString (ZipList a) _______________________________________________ Libraries mailing list Libraries@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/libraries