Re: Improving void

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Edward Kmett writes:

I propose we replace it with

void :: Functor f => f a -> f () void = (() <$)

+1 Edward recently convinced me that 'void' has some hidden costs (over, say, the idiom of "_ <-"), so I'm in favor of anything that may ameliorate those costs. -- John Wiegley FP Complete Haskell tools, training and consulting http://fpcomplete.com johnw on #haskell/irc.freenode.net