Re: Adding swap/compose functions to Data.Tuple and Data.Function

John Wiegley wrote:

Fairly obvious, but strangely missing.

compose :: [(a -> a)] -> a -> a compose = foldr (.) id

-0.5

composeM :: [(a -> m a)] -> a -> m a composeM = foldr (<=<) return

-1 For some reason I would actually expect foldr (>=>) return. Either variant is bound to cause confusion for some people. Bertram