
I'm not sure yet, but I suspect it might be possible to implement
partitionByKeySet more efficiently than the naive way. But to do so,
it will have to construct both pieces eagerly, meaning that using only
part of its result will waste time and allocation.
On Mon, Jul 25, 2016 at 3:34 PM, Andreas Abel
Seems like the partition function would subsume the others?!
partitionByKeys :: Ord k => Set k -> Map k a -> (Map k a, Map k a)
Would there be impressive speed gains for a native
fst . partitionByKeys set
?
On 25.07.2016 20:59, David Feuer wrote:
A final question:
Both `restrictKeys` and `withoutKeys` are special cases of `filterWithKey` (although they should be considerably more efficient than implementations using that function). Do we also want a `partition` special case, in which a map is partitioned into the keys that are in a set and the ones that are not?
On Mon, Jul 25, 2016 at 1:10 PM, Edward Kmett
wrote: Good enough for me.
On Mon, Jul 25, 2016 at 12:11 PM, David Feuer
wrote: I got distracted from this discussion for a bit. Based on input from the list, and Ross Paterson's remark about argument order, I'm currently thinking
restrictKeys :: Ord k => Map k a -> Set k -> Map k a
and
withoutKeys :: Ord k => Map k a -> Set k -> Map k a
Are there any major objections?
On Thu, Jul 14, 2016 at 12:54 PM, Alexey Vagarenko
wrote: How about `keepKeys`?
2016-07-14 21:36 GMT+05:00 Daniel Trstenjak
: On Thu, Jul 14, 2016 at 12:02:51PM -0400, David Feuer wrote: > > If you name it, it will come!
intersectKeys and differentiateKeys
or
intersectionWithSet and differenceWithSet
or ;)
intersectionOfKeys and differenceOfKeys
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-- Andreas Abel <>< Du bist der geliebte Mensch.
Department of Computer Science and Engineering Chalmers and Gothenburg University, Sweden
andreas.abel@gu.se http://www2.tcs.ifi.lmu.de/~abel/ _______________________________________________ Libraries mailing list Libraries@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/libraries