hello, i am trying to write a parser in haskell, using parsec. the task is as follows: a string shall go into a data type (String, [(String, [Integer])]). as an example: "LC.app : 0 , 2 22. abs : 1 ." shall give ("LC", [("app", [0, 2, 22]), ("abs", [1])]) the string is separated by dots, and the integers are separated by either commas or spaces (this is why i cannot use lexer). i have written the following parser, which is not elegant at all, and has the flaw that it does not accept the example because of the space between the 1 and the last dot. furthermore it won't accept newline as a separator for SepBy. -------- the types type Constructor = (String, [Integer]) type Sig = (String, [Constructor]) -- ("LC", [("app", [0, 0]), ("abs", [1])]) -------- the main parser parseString2 :: Parser Sig parseString2 = do spaces name <- word spaces eol sig <- endBy line eol return (name, sig) --------- the parser for one symbol line :: Parser Constructor line = do spaces constru <- word spaces (char ':') spaces ar <- sepBy number separator return (constru, ar) -------- the parser for the integer values number :: Parser Integer number = do ds <- many1 digit; return (read ds) -------- the end of line parser -------- two symbols are separated by at least one point or newline eol :: Parser () eol = do skipMany1 (char '.' <|> char '\n') -------- a separator between two integers is a space or a comma separator :: Parser () separator = skipMany1 (space <|> char ',') i would appreciate if somebody could help me. i tried to exploit all the manuals i found for haskell, but was not successful. greetings ben -- View this message in context: http://www.nabble.com/treating-spaces-with-Parsec-tp20857293p20857293.html Sent from the Haskell - Libraries mailing list archive at Nabble.com.