
It's true that it won't be a runtime hit at all, so the parsing complexity
isn't a concern from that perspective. I *am* worried about making Hamlet
too complicated however. Does anyone else out there have an opinion on this
topic?
Actually, using the new period-not-required syntax, your example could be
rewritten:
[$hamlet|^(template f) x^|]
which is definitely easier on my eyes. However, that syntax would not be
available in $forall, $maybe et al.
Michael
PS: I like your e-mail address.
On Thu, Jul 22, 2010 at 1:49 PM, Mark Bradley
looking at the code it does appear that your grammar for ContentEmbed objects could be extended to include lparen and rparen's. I'm not sure exactly how this would translate with the deref function in Text.Hamlet.Quasi (i havent used template haskell before) but it looks like it is entirely possible, meaning my example would become:
fun f x = [$hamlet| ^(template.f).x^ |]
and all is well. you could add an encoding for this such as:
template.f,x
this would have the same effect as the $ function from regular haskell.
the problem with that encoding is that is it less general than just allowing parens and probably more error prone.
the good thing about this is that it doesn't really matter how complicated you make the encoding and parsing and haskell code generation because it happens once at compile time.
On Wed, Jul 21, 2010 at 2:41 PM, Michael Snoyman
wrote: On Wed, Jul 21, 2010 at 4:17 AM, Mark Bradley
hamlet doesn't appear to support functions that take more than one argument.
i.e.
fun f x = [$hamlet| ^template.f.x^ |]
produces the call template (f x)
is there some way to make hamlet produce (template f) x?
Unfortunately not. It's not any *technical* limitation in Hamlet, just
wrote: that
I can't think of a good, intuitive syntax for it. The way that I work around this is by defining variables in a where clause, eg fun f x = [$hamlet|^templateTmp^|] where templateTmp = template f x If you have better ideas, I'm open to hearing them ;). Michael