(/ 8)
is the same as
(\x -> x / 8)
you can think of it as
(HERE_IS_SOMETHING_MISSING / 8)
whereas
(/) 8
is normal function currying, i.e. it is the same as
(\x -> (/) 8 x)
or
(\x -> 8 / x)
just like
foo y
is the same as
(\x -> foo y x)
if foo is a function that takes 2 parameters.
on the other hand
(8 /)
is like
(8 / HERE_IS_SOMETHING_MISSING)
which translates to
(\x -> 8 / x)
Am 01.07.2013 um 20:03 schrieb Marc Gorenstein
Hi Brandon, Darren, and Michael,
Thanks for you responses, but I'm still confused.
Here are two examples of operator sections. The first takes the infix operator / and turns it into a prefix operator.
Prelude> let eight_div_by = ((/) 8 ) Prelude> eight_div_by 4 2.0
I get that. But look at the following: We now have a prefix operator with the input on the "wrong" side.
Prelude> let div_by_eight = ( / 8 ) Prelude> div_by_eight 4 0.5
Why should ( / 8) 4 = 0.5?
Thanks again,
Marc
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