(/ 8) is the same as (\x -> x / 8) you can think of it as (HERE_IS_SOMETHING_MISSING / 8) whereas (/) 8 is normal function currying, i.e. it is the same as (\x -> (/) 8 x) or (\x -> 8 / x) just like foo y is the same as (\x -> foo y x) if foo is a function that takes 2 parameters. on the other hand (8 /) is like (8 / HERE_IS_SOMETHING_MISSING) which translates to (\x -> 8 / x) Am 01.07.2013 um 20:03 schrieb Marc Gorenstein <marc.gorenstein@gmail.com>:
Hi Brandon, Darren, and Michael,
Thanks for you responses, but I'm still confused.
Here are two examples of operator sections. The first takes the infix operator / and turns it into a prefix operator.
Prelude> let eight_div_by = ((/) 8 ) Prelude> eight_div_by 4 2.0
I get that. But look at the following: We now have a prefix operator with the input on the "wrong" side.
Prelude> let div_by_eight = ( / 8 ) Prelude> div_by_eight 4 0.5
Why should ( / 8) 4 = 0.5?
Thanks again,
Marc
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