
9 Jul
2012
9 Jul
'12
5:26 p.m.
Then think of another approach to doing the problem. :) On Mon, Jul 9, 2012 at 1:30 PM, Carlos J. G. Duarte < carlos.j.g.duarte@gmail.com> wrote:
Thanks, that's it. I had just to move the underK call inside the if:
underK k (x:xs) = if x < k then x : underK k xs else []
... I'm finding this to be a little too awkward to me!
-- -- Regards, KC