21 Feb
2017
21 Feb
'17
1:06 p.m.
I did, sorry! On Tue, 21 Feb 2017 at 15:53 Olumide <50295@web.de> wrote:
On 21/02/2017 15:08, Benjamin Edwards wrote:
The thing that you might also be missing is that function application binds tightest. Hopefully the parenthesis that Rahul has added help you out there. If not:
\w -> f (h w) w
f will be applied to the result of (h r) which yields another function, which is then applied to r
Did you mean to write (h w)?
- Olumide
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