5 Jun
2011
5 Jun
'11
4:09 p.m.
On 5 June 2011 16:40, Daniel Fischer
\a b c d e f g h -> foo (bar a b) (baz c d e) f (quux g h)
Just for the fun of it: $ pointfree "\a b c d e f g h -> foo (bar a b) (baz c d e) f (quux g h)" flip flip quux . ((flip . ((flip . ((flip . ((flip . (((.) . (.)) .)) .)) .)) .)) .) . flip flip baz . (((.) . (.) . (.) . foo) .) . bar using: http://hackage.haskell.org/package/pointfree Cheers, Ozgur