Re: [Haskell-beginners] Re: Offside rule for function arguments?

23 Aug 2010

      ...
The indentation on the second line would generate a parse error, the same
as it does now.
What parser error is that? Both
function 0 = 0 where
 fun     1 = 1
function 2 = 2

and

function 0 = 0 where
 fun     1 = 1
 fun     2 = 2

works for me.

/J

On 23 August 2010 11:46, John Smith  wrote:
...
The indentation on the second line would generate a parse error, the same
as it does now.
On 23/08/2010 12:32, Jonas Almström Duregård wrote:
...
Maybe because of this:
function 0 = 0 where
 fun     1 = 1
         2 = 2
The last declaration (2=2) can define either fun or function. I'm not
saying this is a major problem, but there may be
other problems like these.
/J
On 23 August 2010 11:15, Brent Yorgey > wrote:
...
On Mon, Aug 23, 2010 at 09:33:13AM +0300, John Smith wrote:
...
Why doesn't Haskell allow something like this?
fac 0 = 0
    1 = 1
    x = x * fac (x-1)
This would be clearer than repeating the function name each time,
and follow the same pattern as guards and case.
Good question.  I don't know of any particular reason.
-Brent
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