Dear All, This has reminded me that perhaps there is an easier way. I have a Map, whose elements are indexed by a subset of their structure. I.e. if we have MyType = MyType I T T O E Where I T O and E are types defined elsewhere. The Map the indexes elements of type MyType by a pair, (T, T). I want to be able to index by a pair, independent of order. I had thought about indexing by a pair of pairs, where the elemtns could be the same but reversed. However, the alternative might be to index by a pair, but define that pair as a type, and alter its Eq => definition: MyPair = (T, T) where (t, t') == (t', t) -- I know this syntax is wrong I could then use that as the index to the Map. Does that approach make some sense? Thanks, Matt On Tue, 23 Jun 2015 15:33 Kostiantyn Rybnikov <k-bx@k-bx.com> wrote:
Imants,
You are right. The problem is not in IO here, it's that if you have access to data-constructor, you can do things like:
six :: TypeValInt 6 six = TypeValInt 5
Initially, I was making an assumption that you won't be using a data-constructor. After thinking about it a bit, I should note that my code isn't much different from just using a "smart constructor" approach, e.g. hiding a real MyP constructor, and instead providing a function:
mkMyP (a, b) = MyP (a, b) (b, a)
and exporting only this function. This would make sure all your users only create a valid set of data.
On Tue, Jun 23, 2015 at 5:05 PM, Imants Cekusins <imantc@gmail.com> wrote:
On 23 June 2015 at 14:54, Kostiantyn Rybnikov <k-bx@k-bx.com> wrote:
Hi Matt. I don't know how bad is this, but here's what I came up with. ...
this modified for IO version accepts any input, including that which should have caused error:
or did I do something wrong?
{-# LANGUAGE DataKinds #-} {-# LANGUAGE KindSignatures #-} {-# LANGUAGE ExistentialQuantification #-} {-# LANGUAGE PolyKinds #-} {-# LANGUAGE StandaloneDeriving #-}
module PairsMatchedKR where
import GHC.TypeLits
data TypeValInt (n::Nat) = TypeValInt Int deriving (Show)
one :: TypeValInt 1 one = TypeValInt 1
two :: TypeValInt 2 two = TypeValInt 2
data MyP a b = MyP (TypeValInt a, TypeValInt b) (TypeValInt b, TypeValInt a) deriving (Show)
main :: IO () main = do putStrLn "Hello!" x1 <- getLine x2 <- getLine x3 <- getLine x4 <- getLine
print (MyP (tvi x1, tvi x2) (tvi x3, tvi x4))
class TypeVal (g :: a -> *) instance TypeVal TypeValInt
data MyPGen a b = forall g. (TypeVal g, Show (g a), Show (g b)) => MyPGen (g a, g b) (g b, g a) deriving instance Show (MyPGen a b)
tvi:: String -> TypeValInt (n::Nat) tvi = TypeValInt . read _______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners
_______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners