Re: [Haskell-beginners] Simple function comparison

That's great, thanks. Matt At 11:53 26/11/2015, you wrote:
On Thu, Nov 26, 2015 at 6:20 PM, MJ Williams <mailto:matthewjwilliams101@gmail.commatthewjwilliams101@gmail.com> wrote:
therefore f ( g a ) = g ( f a ) . (transitivity)
If you're interested in getting a firm grasp of airtight proofs -- with a view toward Haskell (and Agda and Idris) mastery -- you might want to pick and choose your way through the web-based proof exercises here:
https://www.coursera.org/course/intrologichttps://www.coursera.org/course/intrologic
This is a course firmly in the American analytic philosophy tradition, so Logic here is Symbolic Logic. Bonus: the course keeps AI and Machine Learning applications in the backdrop.
It's unfortunate that it's some kind of well-kept secret.
Those who don't need it -- because they've obtained the knowledge elsewhere -- won't know about it. And those who do want that knowledge also won't know about it.
Did I mention the exercises are web-based? Yes, you get instantaneous feedback on whether you've got a correct proof or not.
-- Kim-Ee _______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners
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MJ Williams