- Haskell-Cafe - Haskell.org

install 7.8.4 64 bits on arch linux
by Kees Bleijenberg 13 Mar '15

13 Mar '15

I want to upgrade from 7.8.3 32 bits to 7.8.4 64 bits on Arch Linux. So I removed ghc, cabal etc and followed the instruction at: http://sapiengames.com/2014/04/05/install-haskell-platform-arch-linux/ Added the lines [haskell-core] Server = http://xsounds.org/~haskell/core/$arch to pacman.conf added the pacman-key as described updated pacman and finally the fun parts should start.. $ sudo pacman -S ghc cabal-install happy alex looking for inter-conflicts... error: failed to prepare transaction (could not satisfy dependencies) :: haddock: requires ghc=7.8.3-2 :: haskell-ghc-paths: requires ghc=7.8.3-1 What is wrong and what can I do? Kees

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ANNOUNCE: Euterpea 1.0.0
by Daniel Winograd-Cort 13 Mar '15

13 Mar '15

We are happy to announce the official release of Euterpea! Euterpea is a library for computer music research, education, and development, providing both note-level and signal-level abstractions. It is a descendant of Haskore and HasSound and is intended for both educational purposes as well as serious computer music applications. Euterpea is suitable for high-level music representation, algorithmic composition, and analysis; mid-level concepts such as MIDI; and low-level audio processing, sound synthesis, and instrument design. It also includes an extensible system for building musical user interfaces using UISF, a new AFRP UI library. Euterpea's performance is sufficient for most real-time midi applications and some basic real-time audio synthesis. Try it out with cabal install Euterpea You can find more at... euterpea.com - a site for a quick start, tutorials, and working examples haskell.cs.yale.edu/euterpea - more detailed info and help, including an in-progress textbook (Haskell School of Music) hackage.haskell.org/package/Euterpea - the hackage page with some docs

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Additional functionality using cabal configure flags
by Sumit Sahrawat, Maths & Computing, IIT (BHU) 13 Mar '15

13 Mar '15

Hi everybody, I am looking for the correct way to provide additional functionality using cabal configure flags. Even though the developer faq [1] says that it is not recommended, I don't see any downsides for an executable package. Is it 'not recommended' even for executable packages? If not, then how can I do it? [1]: https://wiki.haskell.org/Cabal/Developer-FAQ -- Regards Sumit Sahrawat

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Haskell Weekly News: Issue 320
by Semen Trygubenko / Семен Тригубен ко 13 Mar '15

13 Mar '15

New Releases The sbv package SBV can now generate proof goals that are discharged by ABC, using state-of-the-art SAT based techniques, has better support for IEEE-floats, and a reworked implementation of the connection to the Boolector solver. http://hackage.haskell.org/package/sbv-4.1 Talks Stop Treading Water: Learning to Learn A talk about the alternative to Feynman's algorithm (that can be taught), the total cost of using wrong solutions (integrated over your entire career), the dual of "How to be a Genius" (and how to become a Genius Consultant), and how to beat the exponential decay of human memory (using Spaced Repetition and Going Deeper When You Come Back strategies)! https://yow.eventer.com/yow-2014-1222/stop-treading-water-learning-to-learn… Discussion Solutions in search of problems and problems in search of solutions A comment by Edward Kmett. http://www.reddit.com/r/haskell/comments/2yfris/stop_treading_water_learnin… Once you've seen the beautiful, you don't want to go back to the ugly Discussion of which Haskell ways can benefit what other languages and how to stay employed and satisfied. http://www.reddit.com/r/haskell/comments/2y47rf/once_youve_seen_the_beautif… Learning Haskell — A Racket programmer's documentation of her foray into the land of Haskell (inspired by Learning Racket) Days 0 through 2 are documented so far. http://lexi-lambda.github.io/learning-haskell/ What imperative languages do Haskellers like? Haskell is at the top of the list, followed by C++. http://www.reddit.com/r/haskell/comments/2yqnst/what_imperative_languages_d… Quotes of the Week "Practically every modern human has at least half an hour of spare time a day. If you want to fill that with textbooks or Better Call Saul is up to you." (kqr) "Fritz Henglein's work on discrimination gives you linear time versions of almost everything." (edwardkmett) http://www.reddit.com/r/haskell/comments/2yfris/stop_treading_water_learnin… "I think learning C is just as enlightening as learning Haskell. It forces you to get intimate with your machine in ways other languages (including C++) actively discourage or even forbid." (TheManaKnight) "It seems that after trying haskell not only you can not write anything in other languages, but also you can not solve any problem without going to the deep of it and discover something that truly solves the problem in the deeper sense." (agocorona) http://www.reddit.com/r/haskell/comments/2y47rf/once_youve_seen_the_beautif… "How do I use lens confusing?" "You mean 'it's confusing'" "No, I mean Control.Lens.Traversal.confusing" (cocharles) http://hackage.haskell.org/package/lens-4.8/docs/Control-Lens-Traversal.htm…

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Re: [Haskell-cafe] Is there a name for this?
by Olaf Klinke 12 Mar '15

12 Mar '15

On 2015-03-09 11:26 AM, Ben Franksen wrote: >> Albert Y. C. Lai wrote: >>> Choose one: >>> >>> Foo' is a free Foo >>> >>> Foo' is a limit of the diagram of Foo >>> >>> Foo' is a terminal object of the [sub]category of Foo >> >> Interesting. Is the last variant how "free <whatever>" is usually defined? >> Or is it a coincidence that the two, well, coincide here? I remember I have >> seen other definitions that looked a lot less easy to understand. > > I have not checked, and too lazy to. > > The usual "free" is the less-easy-to-understand one: you need a > forgetful functor, then you need its left adjoint, and you call it your > free functor. Then the target objects hit by the free functor are the > free things. In general when talking about free things and adjunctions one must pay attention to what the functions are. The original definition of class Foo was coalgebraic: class Foo f where bar :: f -> Bool baz :: f -> Char -> Int meaning that the functions take an f and make something else rather than taking something and constructing an f (like e.g. the (:) of lists does). With the definition data Foo' = { bar' :: Bool, baz' :: Char -> Int} one can re-write class Foo f where barbaz :: f -> Foo’ Objects of our category Foo are instances of Foo, that are pairs <f,barbaz> where f is a Haskell type and barbaz is a function f -> Foo’. What are the morphisms? Well, we can consider Foo’ as a phantom type data F a = F Foo’ that is, a constant functor. Then instances of Foo are coalgebras for the functor F, and the right notion of function between coalgebras requires that some equations hold, namely: any h :: f -> f’ that wants to be a Foo-function must have barbaz . h = barbaz. Now we can see that Foo’ is indeed terminal: More precisely, the Foo-instance <Foo’,barbaz=id> is terminal. Indeed, if we have some h :: f -> Foo’ with id . h = barbaz then h must be barbaz, so there is precisely one Foo-function from the Foo-instance <f,barbaz> to <Foo’,id>. I can’t see how Foo’ would be the free Foo in this category, however. Things change if we let Foo-functions be arbitrary functions. Then the documentation of the free package tells us that the free Foo over type t is the instance <(Foo’,t),barbaz=fst>. Olaf

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Deriving Show for non-regular data types
by Mark Laws 12 Mar '15

12 Mar '15

Hi, As part of studying Okasaki's PFDS book, I wanted to add Show support for each of the data structures, and some have proven to be challenging, as some of the types are non-regular and automatic derivation of Show doesn't work. I've been able to add some code that introduces a supplementary type class that serves as a way to pass "proof" that the wrapping data type supports traversal for Show-ability, but the solution seems unsatisfactory. I would greatly appreciate any suggestions for improvements. I've attached the code; the relevant bits are in BankersDeque.hs, Example.hs, NestedShowable.hs, and SimpleCatenableDeque.hs. The same code is available here: https://gist.github.com/drvink/30fb2a2b257fc99af281 Thanks, Mark Laws -- |v\ /\ |\ |< |_ /\ \^| //

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Bad recursion? When can something be on both sides of an equation?
by Jeffrey Brown 12 Mar '15

12 Mar '15

Dear Haskellers, In another thread [1], I talked about computing what I've been lately calling the "total descendents" of a subset S of a graph: that is, the set of nodes t for which every maximal sequence of predecessors intersects S. I got it done, functionally [2]. But in the process I wrote something that hangs, and I can't figure out why. The problem arose in the following passage. (Glab stands for Graph Label, a synonym for Int.) totalDescendents :: S.Set Glab -> Graph -> S.Set Glab totalDescendents roots graph = b where (a,b,c,graph) = totalDescendentsCtrlr -- tricky (roots, S.empty, M.empty, graph) totalDescendentsCtrlr :: TotalDescendentsData -> TotalDescendentsData totalDescendentsCtrlr (a,b,c,gr) = if S.null a' -- fails, as does a == a' -- a == a' is one iteration slower but should have same effect then (a',b',c',gr') else totalDescendentsCtrlr (a',b',c',gr') where (a',b',c',gr') = visitUndetPrds $ visitTdSnvSucs (a,b,c,gr) Notice that in the equation marked "tricky", the object "graph" appears on both sides. I thought that was the problem, so I rewrote that line as the following: where (_,b,_,_) = totalDescendentsCtrlr and sure enough, the problem vanished. So I tried to distill that problem to something tiny, and came up with this: f (a) = a' where (a',b) = fBackend (a,b) -- tricky fBackend (a,b) = if a' < 1 then (a',b) else fBackend (a',b) where a' = a - 1 I see no substantive difference between the problem with the first body of code and the problem I expected f and fBackend to have -- but f and fBackend work fine! Any idea what might be happening? Thanks, Jeff [1] http://permalink.gmane.org/gmane.comp.lang.haskell.cafe/115353 [2] https://github.com/JeffreyBenjaminBrown/digraphs-on-text/blob/master/TotalD…

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Layout rules for if then else
by Alan & Kim Zimmerman 12 Mar '15

12 Mar '15

I am working on ghc-exactprint, and need to flag points where layout must be preserved, and considering the `if` statement. My understanding of the layout rules for if then else is that the `then` has to start more to the right than the `if`. Using GHC 7.10 RC2, ghci cheerfully loads the following ``` f = if True then 1 else 2 ``` Is this valid? Have the rules been relaxed? Alan

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Monadic/sequential migration implementation for data in acid-state
by Sybils Leaf 12 Mar '15

12 Mar '15

Full description of my problem is on Stack Overflow: http://stackoverflow.com/questions/29011479/how-can-a-monadic-sequential-mi… Any comments or suggestions would be greatly appreciated!

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TH not compiling when writing the code directly does
by Michael Jones 12 Mar '15

12 Mar '15

I’m stuck getting a TH expansion to compile. When I take the generated code and compile it directly, it is fine. But when expanding and compiling, it fails. The problem seems related to instanceD, where I provide the type as: (appT (appT (conT devName') (varT $ mkName "Word8")) (varT $ mkName "BV”)) which expands to: IDENTIFICATION__MODEL_ID Word8 BV No matter what I put for the second type (BV), it generates the compile error. For example, Word8 or Word16 gives the same error. But if I take the resulting expression and just put it into the file and compile, it compiles fine. So something about expansion is causing the problem. Is there some more correct way to make the expression rather than nesting two appT? Any ideas? Note: the generation of the functions with (map (\f -> returnQ f) (concat funs)) is ugly in my opinion. I could not find the right way to express this. So all ideas welcome. Mike GEN DEC -------------- makeInstance :: String -> [String] -> Q [Dec] makeInstance devName regNames = do let devName' = mkName devName let regNames' = map mkName regNames let ctx = return [] :: Q [Pred] funs <- mapM (\regName -> [d| $(varP regName) = $(varE $ mkName "writeReadField") $(stringE $ nameBase regName)(get fi) (set fi) where fi = $(conE $ mkName "FieldInfo") 3 1 get info = $(varE $ mkName "getValue") info set info = $(varE $ mkName "setValue") info |]) regNames' instance_ <- instanceD ctx (appT (appT (conT devName') (varT $ mkName "Word8")) (varT $ mkName "BV")) (map (\f -> returnQ f) (concat funs)) return [instance_] COMPILE ERROR ------------------------- src/TestFields.hs:175:3: Illegal type variable name: ‘BV’ When splicing a TH declaration: instance IDENTIFICATION__MODEL_ID Word8 BV where id = writeReadField "id" (get_0 fi_1) (set_2 fi_1) where fi_1 = FieldInfo 3 1 get_0 info_3 = getValue info_3 set_2 info_4 = setValue info_4 ids = writeReadField "ids" (get_5 fi_6) (set_7 fi_6) where fi_6 = FieldInfo 3 1 get_5 info_8 = getValue info_8 set_7 info_9 = setValue info_9

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