Re: [Haskell-cafe] question regarding the $ apply operator

On Tue, Jul 19, 2011 at 02:16, Ting Lei wrote:

I have a naive question regarding the basic use of the $ operator, and I am confused why certain times it doesn't seem to work. e.g. The following works:

applySkip i f ls = (take i) ls ++ f (drop i ls)

But the following doesn't:

applySkip i f ls = (take i) ls ++ f $ drop i ls

($) has lower precedence than almost every other operator, so your "doesn't work" translates to

applySkip i f ls = ((take i) ls ++ f) $ (drop i ls)

-- brandon s allbery allbery.b@gmail.com wandering unix systems administrator (available) (412) 475-9364 vm/sms