Cool!
Is there *anything* Haskell *can't* do?
Michael
--- On Mon, 5/18/09, David Menendez
Unfortunately, you can't derive Show on Chain as defined, because it contains a function:
Sure you can. I just tried the following, and it compiled without complaints.
import Text.Show.Functions
data Chain = Link Int (Int -> Chain) deriving (Show)
The usual warnings about orphan instances apply, but the purpose of
the Text.Show.Functions module is to provide a standard Show instance
for functions so that libraries (e.g., QuickCheck) don't declare
conflicting instances.
--
Dave Menendez