Thinking from subway (: foldl ($) LongDef values ? вторник, 25 декабря 2012 г. пользователь Тимур Амиров писал:
Try folding over data type constructor with $?
вторник, 25 декабря 2012 г. пользователь Magicloud Magiclouds писал:
Forgot to mention, solution without TemplateHaskell.
On Tue, Dec 25, 2012 at 4:59 PM, Magicloud Magiclouds < magicloud.magiclouds@gmail.com> wrote:
Say I have things like:
data LongDec = LongDef a b c ... x y z values = [ 'a', 'b', 'c', ... 'x', 'y', 'z' ]
Now I want them to be "LongDef 'a' 'b' 'c' ... 'x' 'y' 'z'". In form, this is something like folding. But since the type changes, so code like following won't work:
foldl (\def value -> def value) LongDef values
Is it possible to do this in some way? -- 竹密岂妨流水过 山高哪阻野云飞
And for G+, please use magiclouds#gmail.com.
-- 竹密岂妨流水过 山高哪阻野云飞
And for G+, please use magiclouds#gmail.com.
-- Best Timur DeTeam Amirov Moscow, Russia
-- Best Timur DeTeam Amirov Moscow, Russia