Re: [Haskell-cafe] Haskell and "memoization"

It does compute the result of a function application more than once if you ask for it more than once, and that's why we need memoization. Dan On Tue, Dec 15, 2009 at 10:32 PM, michael rice <nowgate@yahoo.com> wrote:

I'm looking here at the Fibonacci stuff:

http://www.haskell.org/haskellwiki/Memoization

Since (I've read) Haskell never computes the value of a function more than once, I don't understand the need for memoization.

Enlighten me.

Michael

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