12 Mar
2008
12 Mar
'08
9:30 p.m.
On 3/12/08, Neil Mitchell <ndmitchell@gmail.com> wrote:
However, I don't believe this expression is type safe in Haskell.
Using higher-order polymorphism: f (x :: forall a. a -> a) = x x -- Taral <taralx@gmail.com> "Please let me know if there's any further trouble I can give you." -- Unknown