Re: [Haskell-cafe] Simple Parsec example, question

15 Sep 2010

      Daniel,
Thanks much; the more I learn Haskell and Parsec, the more I like them.
-- Peter

On Wed, Sep 15, 2010 at 4:02 PM, Daniel Fischer
 wrote:
...
On Wednesday 15 September 2010 23:01:34, Peter Schmitz wrote:
...
...
textLine :: Parser String
textLine = do
   x <- many (noneOf "\n")
   char '\n'
   return x
textLines :: Parser [String]
textLines = many textLine
And it can probably be coded more succinctly that that (suggestions
welcome).
textLine = manyTill anyChar (char '\n')