16 Sep
2010
16 Sep
'10
8 a.m.
Daniel, Thanks much; the more I learn Haskell and Parsec, the more I like them. -- Peter On Wed, Sep 15, 2010 at 4:02 PM, Daniel Fischer <daniel.is.fischer@web.de> wrote:
On Wednesday 15 September 2010 23:01:34, Peter Schmitz wrote:
textLine :: Parser String textLine = do x <- many (noneOf "\n") char '\n' return x
textLines :: Parser [String] textLines = many textLine
And it can probably be coded more succinctly that that (suggestions welcome).
textLine = manyTill anyChar (char '\n')