Fwd: [Haskell-cafe] x -> String

yep add Show to your abstrac container. , for example: data SDynamic= forall a.Show a => SDynamic a instance Show SDynamic where show (SDynamic a)= show a 2009/10/16 David Virebayre

On Fri, Oct 16, 2009 at 8:19 PM, Andrew Coppin

wrote:

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Is there any way that you can turn an arbitrary Haskell value into a string?

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I rephrase: There *is* a way to turn arbitrary values into strings. I know there is, because the GHCi debugger *does* it. The question is, does anybody know of an /easy/ way to do this?

Ghci only displays values with a Show instance. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe