Re: [Haskell-cafe] Convert IO Int to Int

You can not convert an IO Int to Int, or at least, you shouldn't. However, you can do as follows: test :: IO () test = do int <- randomRIO -- or whatever it is called print $ useInt int useInt :: Int -> Int useInt x = x+10 //Tobias 2009/6/9 ptrash <ptrash@web.de>:

Hi,

I am using the System.Random method randomRIO. How can I convert its output to an Int?

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